1 实体类的 Json 序列化和反序列化
我们以如下的 Person 类举例，其中包含了常用的数据类型：
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public class Person{ public int ID { get; set; } public string Name { get; set; } public DateTime Birthday { get; set; } public bool IsVIP { get; set; } public float Account { get; set; } public string[] Favorites { get; set; } public string Remark { get; set; }} |
创建一个 Person 实例：
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Person person = new Person{ ID = 1, Name = "张三", Birthday = DateTime.Parse("2000-01-02"), IsVIP = true, Account = 12.34f, Favorites = new string[] { "吃饭", "睡觉" }}; |
1.1 Json 序列化
返回不缩进的 Json 字符串
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JsonConvert.SerializeObject(person);{"ID":1,"Name":"张三","Birthday":"2000-01-02T00:00:00","IsVIP":true,"Account":12.34,"Favorites":["吃饭","睡觉"],"Remark":null} |
返回缩进的 Json 字符串
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JsonConvert.SerializeObject(person, Formatting.Indented);{ "ID": 1, "Name": "张三", "Birthday": "2000-01-02T00:00:00", "IsVIP": true, "Account": 12.34, "Favorites": [ "吃饭", "睡觉" ], "Remark": null} |
1.2 将不缩进的 JSON 字符串转成缩进形式
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private string JsonIndentation(string str){ //string str = JsonConvert.SerializeObject(entity); JsonSerializer serializer = new JsonSerializer(); TextReader tr = new StringReader(str); JsonTextReader jtr = new JsonTextReader(tr); object obj = serializer.Deserialize(jtr); if (obj != null) { StringWriter textWriter = new StringWriter(); JsonTextWriter jsonWriter = new JsonTextWriter(textWriter) { Formatting = Formatting.Indented, Indentation = 4, IndentChar = ' ' }; serializer.Serialize(jsonWriter, obj); return textWriter.ToString(); } else { return str; }} |
或者：
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private string JsonIndentation(string json){ JObject obj = JObject.Parse(json); return obj.ToString();} |
1.3 其他设置
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JsonSerializerSettings settings = new JsonSerializerSettings();// 设置日期格式settings.DateFormatString = "yyyy-MM-dd";// 忽略空值settings.NullValueHandling = NullValueHandling.Ignore;// 缩进settings.Formatting = Formatting.Indented;JsonConvert.SerializeObject(person, settings); |
返回：
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{ "ID": 1, "Name": "张三", "Birthday": "2000-01-02", "IsVIP": true, "Account": 12.34, "Favorites": [ "吃饭", "睡觉" ]} |
1.4 Json 反序列化
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JsonConvert.DeserializeObject<Person>(json); |
2 JObject 使用
2.1 创建对象
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JObject obj = new JObject();obj.Add("ID", 1);obj.Add("Name", "张三");obj.Add("Birthday", DateTime.Parse("2000-01-02"));obj.Add("IsVIP", true);obj.Add("Account", 12.34f);// 创建数组JArray array = new JArray();array.Add(new JValue("吃饭"));array.Add(new JValue("睡觉"));obj.Add("Favorites", array);obj.Add("Remark", null); |
2.2 JObject 中添加数组
上例中的代码可以简化为：
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JArray array = new JArray("吃饭", "睡觉"); |
2.3 从 Json 字符串创建 JObject
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string json = "{\"ID\":1,\"Name\":\"张三\",\"Birthday\":\"2000-01-02T00:00:00\",\"IsVIP\":true,\"Account\":12.34,\"Favorites\":[\"吃饭\",\"睡觉\"],\"Remark\":null}";JObject obj = JObject.Parse(json); |
2.4 从 Entity 创建 JObject
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JObject obj = JObject.FromObject(person); |
用匿名对象创建 JObject
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JObject obj = JObject.FromObject(new { name = "jack", age = 18 });//显示{ "name": "jack", "age": 18} |
用初始化器
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JObject obj = new JObject(){ { "name", "jack" }, { "age", 18 }}; |
#21b611ff951f9ef061490f6f234ef4bc#
2.5 获取值
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int id;if (obj["ID"] != null) id = obj["ID"].Value<int>(); |
2.6 获取数组
Newtonsoft.Json.Linq 不支持直接获取数组，但是可以获取 List，然后再转化为数组。
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string[] favorites;if (obj["Favorites"] != null) favorites = obj["Favorites"].Value<List<string>>().ToArray(); |
以上就是c# Newtonsoft.Json 常用方法总结的详细内容，更多关于c# Newtonsoft.Json的资料请关注服务器之家其它相关文章！
原文链接：https://www.cnblogs.com/gl1573/p/11660202.html
