用shell写的递归遍历目录的脚本，脚本实现递归遍历指定目录，打印目录下的文件名。
实例1：
#!/bin/sh
function scandir() {
local cur_dir parent_dir workdir
workdir=$1
cd ${workdir}
if [ ${workdir} = "/" ]
then
cur_dir=""
else
cur_dir=$(pwd)
fi
for dirlist in $(ls ${cur_dir})
do
if test -d ${dirlist};then
cd ${dirlist}
scandir ${cur_dir}/${dirlist}
cd ..
else
echo ${cur_dir}/${dirlist}
fi
done
}
if test -d $1
then
scandir $1
elif test -f $1
then
echo "you input a file but not a directory,pls reinput and try again"
exit 1
else
echo "the Directory isn't exist which you input,pls input a new one!!"
exit 1
fi
实例2：递归读取目录及其子目录
#! /bin/bash
function read_dir(){
for file in `ls $1`
do
if [ -d $1"/"$file ] //注意此处之间一定要加上空格，否则会报错
then
read_dir $1"/"$file
else
echo $1"/"$file
fi
done
}
#测试目录 test
read_dir test
这样给test.sh加上执行权限即可执行
sh test.sh
到此即可通过传递参数来读取目录文件了。
实例3：
递归实现各个子目录孙目录......
#!/bin/bash
#modify.func
doit() //处理当前目录下的非目录文件，忽略目录文件
{
oldname=`ls | grep "$1$"`
for name in $oldname
do
if [ -d "$name" ]
then :
else
basename=`echo $name | awk -F "." '{print $1}'`
newname="$basename$2"
echo -e "$PWD/$name\t\t$newname"
mv $name $newname
count=`expr ${count} + 1`
fi
done
return 0
}
do_recursive() //从当前目录开始，递归处理各目录
{
doit $1 $2
for filename in `ls`
do
if [ -d "$filename" ]
then
cd $filename
do_recursive $1 $2
cd ..
fi
done
return 0
}
modify() //处理当前目录，并报告结果，这个相当于主函数，也可以直接调用do_recursive
{
PARAMS=2
if [ $# -ne $PARAMS ]
then
echo "usage: mv_to .suf1 .suf2"
return 1
fi
count=0
do_recursive $1 $2
echo "complete! $count files have been modified."
return 0
}
