本文实例为大家分享了C语言实现简易计算器功能的具体代码,供大家参考,具体内容如下
表达式求值项目(多功能计算器)。该项目主要包含了10个模块,10项功能:
1:加法运算:主要进行两个数的加法运算,可进行计算整数和浮点数;
2:减法运算:主要进行两个数的减法运算,可进行计算整数和浮点数;
3:乘法运算:主要进行两个数的乘法运算,可进行计算整数和浮点数;
4:除法运算:主要进行两个数的除法运算,可进行计算整数和浮点数;增加了报错功能,由于除数不可以为0,当用户输入的除数为0的时候,该项目会出提示红色字体提示语句,提醒用户输入有误重新输入。
5:开平方根:主要进行某个数的开方,选择该功能时,计算器会提示输入需开方的数,然后打印出开方后的结果;
6:求某数的N次幂:选择该功能时,计算器会提示请输入需要计算的数x以及N的值,然后打印出N次幂后的结果;
7:进位制的转换:任意输入某个数字,可以将该数字分别转换为二进制,八进制,和十六进制。
8:表达式求值:
9:一元二次方程求解:
10:中缀表达式转换为后缀表达式:输入表达式后,计算器会对表达式进行判断。判断括号是否匹配,括号匹配完成后进行下一步表达式运算符匹配,匹配成功后输出其后缀表达式。如果匹配出现错误,出现红色字体警告,发出哔哔的声音,提示重新输入。
0:退出功能:选择退出时,出现一个退出界面。并退出程序。
小功能介绍:计算器包含了3个界面,开始界面,菜单界面,退出界面。采用多级变色提示音,红,绿,紫,黄。方便用户操作和查看。
开始界面如图:
功能界面如图:
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#include<stdio.h> #include<windows.h> #include<stdlib.h> #include<math.h> #define MaxSize 10000 void print2(); void print1(); struct Stackop { char op[MaxSize]; int top; } stackop; struct StackNum { double num[MaxSize]; int top; } stacknum; int GetLevel( char op) //得到运算符的优先等级 { if (op== '+' ||op== '-' ) return 1; if (op== '*' ||op== '/' ) return 2; return 0; } double Add( double a, double b) //加法运算 { return a+b; } double Sub( double a, double b) //减法运算 { return a-b; } double Multi( double a, double b) //乘法运算 { return a*b; } double Div( double a, double b, double *result) //除法运算 { if (b==0) printf ( "除数不能为0\n" ); return 0; *result=a/b; return 1; } int Calculate( double a, double b, char op, double *result) //用于对两个数进行运算 { switch (op) { case '+' : *result=Add(a,b); return 1; case '-' : *result=Sub(a,b); return 1; case '*' : *result=Multi(a,b); return 1; case '/' : return Div(a,b,result); default : return 0; } } void GetRpn( char *str, char *rpn) { int len= strlen (str),cnt=0,i; int isnum=0; stackop.top=-1; if (str[len-1]== '=' ) len--; if (str[0]== '-' ) { rpn[cnt++]= '0' ; rpn[cnt++]= '#' ; } for (i=0; i<len; i++) { if (str[i]>= '0' &&str[i]<= '9' ||str[i]== '.' ) { rpn[cnt++]=str[i]; isnum=1; continue ; } if (isnum) { rpn[cnt++]= '#' ; isnum=0; } if (str[i]== '(' &&str[i+1]== '-' ) { rpn[cnt++]= '0' ; rpn[cnt++]= '#' ; } if (str[i]== '(' ) stackop.op[++stackop.top]=str[i]; else if (str[i]== ')' ) { while (stackop.op[stackop.top]!= '(' ) { rpn[cnt++]=stackop.op[stackop.top]; stackop.top--; } stackop.top--; } else if (stackop.top!=-1&&GetLevel(str[i])<= GetLevel(stackop.op[stackop.top])) { while (stackop.top!=-1&&GetLevel(str[i])<= GetLevel(stackop.op[stackop.top])) { rpn[cnt++]=stackop.op[stackop.top]; stackop.top--; } stackop.op[++stackop.top]=str[i]; } else { stackop.op[++stackop.top]=str[i]; } } if (isnum) rpn[cnt++]= '#' ; while (stackop.top!=-1) { rpn[cnt++]=stackop.op[stackop.top]; stackop.top--; } rpn[cnt]= '\0' ; } int GetAns( char *rpn, double *result) { int len= strlen (rpn),i; double fnum; int num,cnt; stacknum.top=-1; for (i=0; i<len; i++) { if (rpn[i]>= '0' &&rpn[i]<= '9' ) { num=cnt=0; fnum=0; while (rpn[i]!= '#' &&rpn[i]!= '.' ) { num=num*10+rpn[i]- '0' ; i++; } if (rpn[i]== '.' ) { i++; while (rpn[i]!= '#' ) { fnum=fnum+(rpn[i]- '0' )*1.0/ pow (10,++cnt); i++; } } fnum+=num; stacknum.num[++stacknum.top]=fnum; } else { double a,b,c; b=stacknum.num[stacknum.top]; stacknum.top--; a=stacknum.num[stacknum.top]; stacknum.top--; if (Calculate(a,b,rpn[i],&c)==0) { //计算失败 return 0; } else { stacknum.num[++stacknum.top]=c; } } } *result=stacknum.num[stacknum.top]; return 1; } int kuohao( char *str) //判断圆括号输入是否正确 { int i,len= strlen (str); int count=0; for (i=0;i<len;i++) { if (str[i]== '(' ) count++; if (str[i]== ')' ) count--; } if (count!=0) { Beep(5000, 300); SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),FOREGROUND_INTENSITY|FOREGROUND_RED); printf ( "\n括号输入有错误\n" ); SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),FOREGROUND_INTENSITY|FOREGROUND_GREEN); return 0; } else printf ( "\n括号匹配正确\n" ); return 1; } int yunsunfu( char *str) { int i,len= strlen (str),k; printf ( "\n判断括号匹配输入是否正确:\n" ); k=kuohao(str); if (k==0) return 0; printf ( "\n判断多项式运算符输入是否正确:\n" ); for (i=0;i<len;i++) { if (str[i]== '+' ||str[i]== '-' ||str[i]== '*' ||str[i]== '/' ) { if (str[i+1]== '(' ||(str[i+1]>= '0' &&str[i+1]<= '9' )) continue ; else { Beep(5000, 300); SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),FOREGROUND_INTENSITY|FOREGROUND_RED); printf ( "\n多项式输入有错误\n" ); SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),FOREGROUND_INTENSITY|FOREGROUND_GREEN); return 0; } } } printf ( "\n多项式输入正确\n" ); return 1; } int main() { HANDLE hOut; // 获取输出流的句柄 hOut = GetStdHandle(STD_OUTPUT_HANDLE); SetConsoleTextAttribute(hOut, FOREGROUND_RED | // 前景色_红色 FOREGROUND_BLUE | // 前景色_蓝色 FOREGROUND_INTENSITY); // 加强 print1(); system ( "pause" ); system ( "cls" ); char str[MaxSize],rpn[MaxSize],ch; double bNumber, Number, Result,result; //给加减乘除定义的变量 double a, b, c,x, x1, x2, Rad; //一元二次方程定义变量 int Ary_10,n; //定义进制的变量 char string[32]; //二进制变量定义 while (1) { switch (menu()) { case 1: printf ( "请输入被加数:" ); scanf ( "%lf" ,&bNumber); printf ( "请输入加数:" ); scanf ( "%lf" ,&Number); Result = bNumber + Number; printf ( " 结果是: %.2lf\n\n" ,Result); if ( scanf ( "%c*%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 2: printf ( " 请输入被减数:" ); scanf ( "%lf" ,&bNumber); printf ( " 请输入减数:" ); scanf ( "%lf" ,&Number); Result = bNumber - Number; printf ( " 结果是: %.2lf\n\n" ,Result); if ( scanf ( "%c*%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 3: printf ( " 请输入被乘数:" ); scanf ( "%lf" ,&bNumber); printf ( " 请输入乘数:" ); scanf ( "%lf" ,&Number); Result = bNumber * Number; printf ( " 结果是: %.2lf\n" ,Result); if ( scanf ( "%c*%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 4: printf ( " 请输入被除数:" ); scanf ( "%lf" ,&bNumber); printf ( " 请输入除数:" ); scanf ( "%lf" ,&Number); if (Number==0) { HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE); // 获取控制台句柄 SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED); // 红色提示 printf ( "除数不可以为零\n" ); if ( scanf ( "%c*%c" ,&ch)== '\0' ); system ( "cls" ); break ; } else { Result = bNumber / Number; printf ( " 结果是: %.2lf\n\n" ,Result); if ( scanf ( "%c*%c" ,&ch)== '\0' ); system ( "cls" ); break ;} case 8: { int k; printf ( "输入所要经计算的表达式(如:a*b/(c-d))\n" ); gets (str); if ( gets (str)!=NULL) { k=yunsunfu(str); if (k!=0) { GetRpn(str,rpn); printf ( "其后缀表达式:%s\n" ,rpn); GetAns(rpn,&result); printf ( "表达式结果:%.2f\n" ,result); if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; } } } case 10: { int k; printf ( "请输入需要转换的表达式并以回车结束:\n" ); gets (str); if ( gets (str)!=NULL) { k=yunsunfu(str); if (k!=0) { GetRpn(str,rpn); printf ( "其后缀表达式:%s\n" ,rpn); if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; } else if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; } else printf ( "表达式为空,请核证后在输入.\n" ); } case 9: { printf ( "请输入一元一次方程的a,b,c三个数:" ); scanf ( "%lf%lf%lf" ,&a,&b,&c); getchar (); Rad = b*b - 4*a*c; if (Rad > 0) { x1 = -b + sqrt (Rad) / (2*a); x2 = -b - sqrt (Rad) / (2*a); printf ( "有两个解 x1 = %.2lf, x2 = %.2lf\n" ,x1,x2); } else if (Rad == 0) { x1 = -b / (2*a); printf ( "只有一个解 x1 = %.2lf\n" ,x1); } else { printf ( "无解\n" ); } if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; } case 7: printf ( "请输入需要转换的十进制数:" ); scanf ( "%d" , &Ary_10); getchar (); itoa (Ary_10, string ,2); printf ( "二进制: %s\n" ,string); printf ( "八进制: %o\n" ,Ary_10); printf ( "十六进制: %x\n" ,Ary_10); if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 5: printf ( "请输入要开平方根的数X:\n" ); scanf ( "%lf" ,&x); getchar (); result= sqrt (x); printf ( "%.2lf开根后的结果:%.2lf" ,x,result); if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 6: printf ( "请输入你要求幂的数X和指数n:" ); scanf ( "%lf%d" ,&x,&n); getchar (); result= pow (x,n); printf ( "%.2lf的%d次幂为%.2lf" ,x,n,result); if ( scanf ( "%c" ,&ch)== '\0' ); system ( "cls" ); break ; case 0: print2(); return 0; } } return 0; } int menu() { int v; HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE); // 获取控制台句柄 SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED | FOREGROUND_GREEN); // 设置为黄色 printf ( "\n" ); printf ( "┏ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┓\n" ); printf ( "┇请选择你要计算的方法: ┇\n" ); printf ( "┣ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┫\n" ); printf ( "┇ 加法请按_1 进制转换_7 ┇\n" ); printf ( "┇ 减法请按_2 表达式求值请按_8 ┇\n" ); printf ( "┇ 乘法请按_3 求一元二次方程_9 ┇\n" ); printf ( "┇ 除法请按_4 中缀表达式转化为后缀表达式_ 10┇\n" ); printf ( "┇ 求平方根_ 5 ┇\n" ); printf ( "┇ 求数的N次幂_6 退出_0 ┇\n" ); printf ( "┗ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┅ ┛\n" ); printf ( "Please write down the number:" ); do { printf ( "请选择(0-10)\n" ); scanf ( "%d" ,&v); } while (v<0||v>10); return v; } void print1() { printf ( "|_______________________________________ | \n" ); printf ( "|| | | \n" ); printf ( "|| 欢迎使用功能计算器 | | 本计算器能够进行 \n" ); printf ( "||_____________________________________| | +,-,×,÷,\n" ); printf ( "|| 图案仅供参考 | | ()等等 \n" ); printf ( "||_____________________________________| | \n" ); printf ( "| | \n" ); printf ( "|___ ___ ___ ___ ___ ___ ___ ___ | \n" ); printf ( "|________ ________ ________ ________ | \n" ); printf ( "|| ⑨ | | ⑧ | | ⑦ | | × | | \n" ); printf ( "||______| |______| |______| |______| | \n" ); printf ( "|________ ________ ________ ________ | \n" ); printf ( "|| ⑥ | | ⑤ | | ④ | | - | | \n" ); printf ( "||______| |______| |______| |______| | \n" ); printf ( "| _______ ________ ________ ________ | \n" ); printf ( "|| ③ | | ② | | ① | | + | | \n" ); printf ( "||______| |______| |______| |______| | \n" ); printf ( "|________ ________ ________ ________ | \n" ); printf ( "|| 〇 | | = | | AC | | ÷ | | \n" ); printf ( "||______| |______| |______| |______| | \n" ); printf ( "|| 版权所有,翻版必究 | \n" ); } void print2() { system ( "cls" ); HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE); // 获取控制台句柄 SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_BLUE); // 设置为蓝色 printf ( "\n\n\n\n\n\n\n\n\t\t\t ##############################\n" ); printf ( "\t\t\t # #\n" ); printf ( "\t\t\t #----------谢谢使用----------#\n" ); printf ( "\t\t\t # #\n" ); printf ( "\t\t\t ##############################\n" ); printf ( "\t\t\t --小李子制作\n " ); } |
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/wuliowen/article/details/51308042