需求分析
根据原始数据，计算出累计和、回撤、连续正确、连续错误、连续正确值与连续错误值6项数据，其中原始数据大于等于0认定为正确，原始数据小于0为错误。明白了要求，那我们就开始撸代码吧~
解决步骤
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import pandas as pd#创建一个计算数据的函数def calculate(df): pass#读取原始数据，将索引列去除df = pd.read_excel('需求0621.xlsx',index_col=0)#调用计算数据的函数calculate(df) |
先把整体思路写好，再去想办法计算每项数据
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#计算累计和 lst1 = [] sum = 0 for i in range(df.shape[0]): if i == 0: lst1.append(df['N'][i]) sum += df['N'][i] else: sum += df['N'][i] lst1.append(sum) df['累计和'] = lst1 |
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#计算回撤 lst2 = [] max = 0 for i in range(df.shape[0]): if i == 0: lst2.append(0) elif df['累计和'][i] > max: max = df['累计和'][i] lst2.append(0) elif df['累计和'][i] < max: lst2.append(df['累计和'][i]-max) elif df['累计和'][i] == max: lst2.append(0) df['回撤'] = lst2 |
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#计算连续正确的个数 lst3 = [] correct = 0 for i in range(df.shape[0]): if df['N'][i] >= 0: correct += 1 lst3.append(correct) else: lst3.append(0) correct = 0 df['连续正确'] = lst3 |
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#计算连续错误的个数 lst4 = [] mistake = 0 for i in range(df.shape[0]): if df['N'][i] < 0: mistake += 1 lst4.append(mistake) else: lst4.append(0) mistake = 0 df['连续错误'] = lst4 |
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#计算连续正确值 lst5 = [] for i in range(df.shape[0]): lst5.append('') right = 0 for i in range(df.shape[0]): if df['连续正确'][i] != 0: right += df['N'][i] elif df['连续正确'][i] == 0 and right != 0: lst5[i-1] = right right = 0 df['连续正确值'] = lst5 |
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#计算连续错误值 lst6 = [] for i in range(df.shape[0]): lst6.append('') wrong = 0 for i in range(df.shape[0]): if df['连续错误'][i] != 0: wrong += df['N'][i] elif df['连续错误'][i] == 0 and wrong != 0: lst6[i-1] = wrong wrong = 0 df['连续错误值'] = lst6 |
最后将dataframe保存到excel
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df.to_excel('完成计算.xlsx')print('保持成功') |
最终结果
技术总结
虽然已经完成了要求计算出了所有的数据，但在写代码过程中计算的步骤都是基于python基础语法实现的，对于pandas的使用还要只有通过大量的练习才能够熟练的掌握
到此这篇关于利用Python实现简单的Excel统计函数的文章就介绍到这了,更多相关Python实现Excel统计函数内容请搜索服务器之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持服务器之家！
原文链接：https://blog.csdn.net/m0_69043821/article/details/125417629
