此解决方式在企业中有所应用,适合Java初级开发学习,参考。
需要修改的报文
当你拿到的报文是这样的
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{ "input" : { "sdfsn" : "23u4209350-2" , "fsfs" : "128412094" , "sgsgsg" : "15821059" , "inssgsuplc_admdfdfdvs" : "125125332" , "dgh" : "125215312" , "dfgdfg" : "215215" , "sdhdsh" : "" , "sdfsn" : "" , "shdfshdshdsh" : "shsdh" , "sdhdsh" : "shsh.0" , "shsdhsd" : "1" , "shsdh" : "1607" , "input" : { "data" : { "dhfsdhsd" : "235325" , "shsdhsdh" : "03" , "dgd" : "BE0445360" , "dfhfdh" : "11" , "dshshsd" : 76.56 , "ghjrfgj" : "01" , "grjf" : "234623626" , "hjfd" : "236436" , "djfdfgjdfj" : "45634" , "exp_Content" : "{" gdsg ":" 0 1 "," gjfj ":" 658568 "," fjfj ":" 5675467 "," ghfjfgkj ":" 68568 "," vmgfvj ":" 658568 "," gfhjgfyk ":" 0 "," fghkfghkg ":" 5474567 "}" , "dfjgdfj" : "" , "dfjdfjgdfj" : "56745745" , "dfgjdfgjh" : 45756758 , "jdfgjhfdgj" : 0 , } } }, "output" : { "output" : { "r757" : { "dhfsdhsd" : "235325" , "shsdhsdh" : "03" , "dgd" : "BE0445360" , "dfhfdh" : "11" , "dshshsd" : 76.56 , "ghjrfgj" : "01" , "grjf" : "234623626" , "hjfd" : "236436" , "djfdfgjdfj" : "45634" , "exp_content" : "" , "dfjgdfj" : "" , "dfjdfjgdfj" : "56745745" , "dfgjdfgjh" : 45756758 , "jdfgjhfdgj" : 0 , }, "sdfgsdfg" : [ { "sgasgag" : "4673476" , "agasgdas" : 5675467 , "asgasgasg" : "" , "asdgasgas" : 4567456754 , "dhsdsxchsdh" : 54675467 , "sdfhsdhsdh" : "5674756457" } ] }, "erherth" : 0 , } } |
这一看就知道上边的报文在postman里边肯定会报错,因为exp_Content,因此他又没有用到,所以你想把他删掉。其实也没那么难删
也就是用到了流转字符串。字符串固定字符查找,然后进行字符串转字符流,删掉字符流中固定字符,之后再转回来。因为字符串已经是final了所以很多用法都是使用字符串转字符流实现的
实现代码如下
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private JSONObject resolveApplicationJson(HttpServletRequest request) { InputStream is = null ; String json = null ; try { is = request.getInputStream(); json = IOUtils.toString(is, "UTF-8" ); json=json.replaceAll( "\\r|\n|\t" , "" ); int index= json.indexOf( "exp_Content" ); int indexfirst=json.indexOf( "{" , index); int indexlast=json.indexOf( "}" ,index); if (index!=- 1 && indexlast !=- 1 &&indexfirst !=- 1 ) { StringBuffer stringBuffer = new StringBuffer(json); stringBuffer.delete(indexfirst,indexlast+ 1 ); json=stringBuffer.toString(); } } catch (IOException e) { throw new RuntimeException( "CANNOT get reader from request!" , e); } finally { if (is != null ) { try { is.close(); } catch (IOException e) { e.printStackTrace(); } } } try { return new JSONObject(json); } catch (JSONException e) { throw new RuntimeException( "CANOT CONVET JSON:[" + json + "] to JSONObject!" , e); } } |
多存在多个不符合规定的数据然后你要删掉怎么操作呢?
这也很简单,如果你看了这一篇文章,你要更好的解决方式,期待一起探讨,学习进步(^-^)V
当你拿到的报文是这样的。
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{ "input" : { "sdfsn" : "23u4209350-2" , "fsfs" : "128412094" , "sgsgsg" : "15821059" , "inssgsuplc_admdfdfdvs" : "125125332" , "dgh" : "125215312" , "dfgdfg" : "215215" , "sdhdsh" : "" , "sdfsn" : "" , "shdfshdshdsh" : "shsdh" , "sdhdsh" : "shsh.0" , "shsdhsd" : "1" , "shsdh" : "1607" , "input" : { "data" : { "dhfsdhsd" : "235325" , "shsdhsdh" : "03" , "dgd" : "BE0445360" , "dfhfdh" : "11" , "dshshsd" : 76.56 , "ghjrfgj" : "01" , "grjf" : "234623626" , "hjfd" : "236436" , "djfdfgjdfj" : "45634" , "exp_Content" : "{" gdsg ":" 0 1 "," gjfj ":" 658568 "," fjfj ":" 5675467 "," ghfjfgkj ":" 68568 "," vmgfvj ":" 658568 "," gfhjgfyk ":" 0 "," fghkfghkg ":" 5474567 "}" , "dfjgdfj" : "" , "dfjdfjgdfj" : "56745745" , "dfgjdfgjh" : 45756758 , "jdfgjhfdgj" : 0 , } } }, "output" : { "output" : { "r757" : { "dhfsdhsd" : "235325" , "shsdhsdh" : "03" , "dgd" : "BE0445360" , "exp_Content" : "{" gdsg ":" 0 1 "," gjfj ":" 658568 "," fjfj ":" 5675467 "," ghfjfgkj ":" 68568 "," vmgfvj ":" 658568 "," gfhjgfyk ":" 0 "," fghkfghkg ":" 5474567 "}" , "dfhfdh" : "11" , "dshshsd" : 76.56 , "ghjrfgj" : "01" , "grjf" : "234623626" , "hjfd" : "236436" , "djfdfgjdfj" : "45634" , "exp_content" : "{" gdsg ":" 0 1 "," gjfj ":" 658568 "," fjfj ":" 5675467 "," ghfjfgkj ":" 68568 "," vmgfvj ":" 658568 "," gfhjgfyk ":" 0 "," fghkfghkg ":" 5474567 "}" , "dfjgdfj" : "" , "dfjdfjgdfj" : "56745745" , "dfgjdfgjh" : 45756758 , "jdfgjhfdgj" : 0 , }, "sdfgsdfg" : [ { "sgasgag" : "4673476" , "agasgdas" : 5675467 , "asgasgasg" : "" , "asdgasgas" : 4567456754 , "dhsdsxchsdh" : 54675467 , "sdfhsdhsdh" : "5674756457" } ] }, "erherth" : 0 , } } |
解决方式如下:根据需要写出正则表达式,再使用正则看看有几个这样的不需要的符号,然后循环遍历几次,之后找到这部分,最后删除掉。
实现代码如下
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# 全局变量 private static String REGEX = "exp_[c,C]ontent" ; # 方式方法 Pattern p = Pattern.compile(REGEX); // 获取 matcher 对象 Matcher m = p.matcher(JSON); List<Integer> list = new ArrayList(); while (m.find()){ list.add(m.start()); } int index= 0 ; int indexfirst= 0 ; int indexlast= 0 ; for ( int j = 0 ; j < list.size(); j++) { index=JSON.indexOf( "exp_" ,indexlast); indexfirst=JSON.indexOf( "{" , index); indexlast=JSON.indexOf( "}" ,index); StringBuffer stringBuffer = null ; if (indexlast !=- 1 &&indexfirst !=- 1 ) { stringBuffer = new StringBuffer(JSON); stringBuffer.delete(indexfirst,indexlast+ 1 ); } JSON=stringBuffer.toString(); } |
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原文链接:https://juejin.cn/post/7220216152190550071