sql server 递归查询树型结构某节点的所有上级节点,并且把这些所有上级节点多行拼接为一行,即合并列数据
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with eps_root(pk_eps, pk_parent, eps_code, eps_name) as ( SELECT pk_eps, pk_parent, eps_code, eps_name FROM pm_eps where enablestate = 2 and pk_eps = '1001A11000000003P62E' union all SELECT e.pk_eps, e.pk_parent, e.eps_code, e.eps_name FROM pm_eps e inner join eps_root r on e.pk_eps = r.pk_parent where e.enablestate = 2 ) select distinct eps_code = stuff(( select '/' + convert (nvarchar(500), eps_code) from ( select distinct eps_code from eps_root) r1 for xml path( '' )), 1, 1, '' ), --此次需要使用eps_code排序,不然中文的会错乱顺序 eps_name = stuff(( select '/' + eps_name from ( select top 99.99 PERCENT eps_name from eps_root order by eps_code) r2 for xml path( '' )), 1, 1, '' ) from eps_root |
执行sql,如下图效果:
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原文链接:https://blog.csdn.net/u010741112/article/details/128568479