【pytorch官方文档】:https://pytorch.org/docs/stable/generated/torch.nn.AvgPool2d.html?highlight=avgpool2d#torch.nn.AvgPool2d
torch.nn.AvgPool2d()
作用
在由多通道组成的输入特征中进行2D平均池化计算
函数
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torch.nn.AvgPool2d(kernel_size, stride = None , padding = 0 , ceil_mode = False , count_include_pad = True , divisor_override = None ) |
参数
Args:
kernel_size: 滑窗(池化核)大小
stride: 滑窗的移动步长, 默认值为kernel_size
padding: 在输入信号两侧的隐式零填充数量
ceil_mode: 决定计算输出的形状时是向上取整还是向下取整, 默认为False(向下取整)
count_include_pad: 在平均池化计算中是否包含零填充, 默认为True(包含零填充)
divisor_override: 如果指定了, 它将被作为平均池化计算中的除数, 否则将使用池化区域的大小作为平均池化计算的除数
公式
代码实例
假设输入特征为S,输出特征为D
情况一
ceil_mode=False, count_include_pad=True(计算时包含零填充)
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import torch import torch.nn as nn import numpy as np # 生成一个形状为1*1*3*3的张量 x1 = np.array([ [ 1 , 2 , 3 ], [ 4 , 5 , 6 ], [ 7 , 8 , 9 ] ]) x1 = torch.from_numpy(x1). float () x1 = x1.unsqueeze( 0 ).unsqueeze( 0 ) # 实例化二维平均池化 avgpool1 = nn.AvgPool2d(kernel_size = 3 , stride = 2 , padding = 1 , ceil_mode = False , count_include_pad = True ) y1 = avgpool1(x1) print (y1) # 打印结果 ''' tensor([[[[1.3333, 1.7778], [2.6667, 3.1111]]]]) ''' |
计算过程:
输出形状= floor[(3 - 3 + 2) / 2] + 1 = 2,
D[1,1] = (0+0+0+0+1+2+0+4+5) / 9 = 1.3333,
D[1,2] = (0+0+0+2+3+0+5+6+0) / 9 = 1.7778,
D[2,1] = (0+4+5+0+7+8+0+0+0) / 9 = 2.6667,
D[2,2] = (5+6+0+8+9+0+0+0+0) / 9 = 3.1111.
情况二
ceil_mode=False, count_include_pad=False(计算时不包含零填充)
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avgpool2 = nn.AvgPool2d(kernel_size = 3 , stride = 2 , padding = 1 , ceil_mode = False , count_include_pad = False ) y2 = avgpool2(x1) print (y2) # 打印结果 ''' tensor([[[[3., 4.], [6., 7.]]]]) ''' |
计算过程:
输出形状= floor[(3 - 3 + 2) / 2] + 1 = 2,
D[1,1] = (1+2+4+5) / 4 = 3,
D[1,2] = (2+3+5+6) / 4 = 4,
D[2,1] = (4+5+7+8) / 4 = 6,
D[2,2] = (5+6+8+9) / 4 = 7.
情况三
ceil_mode=False, count_include_pad=False, divisor_override=2(将计算平均池化时的除数指定为2)
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avgpool3 = nn.AvgPool2d(kernel_size = 3 , stride = 2 , padding = 1 , ceil_mode = False , count_include_pad = False , divisor_override = 2 ) y3 = avgpool3(x1) print (y3) # 打印结果 ''' tensor([[[[ 6., 8.], [12., 14.]]]]) ''' |
计算过程:
输出形状= floor[(3 - 3 + 2) / 2] + 1 = 2,
D[1,1] = (1+2+4+5) / 2 = 6,
D[1,2] = (2+3+5+6) / 2 = 8,
D[2,1] = (4+5+7+8) / 2 = 12,
D[2,2] = (5+6+8+9) / 2 = 14.
情况四
ceil_mode=True, count_include_pad=True, divisor_override=None(在计算输出的形状时向上取整)
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x2 = np.array([ [ 1 , 2 , 3 , 4 ], [ 5 , 6 , 7 , 8 ], [ 9 , 10 , 11 , 12 ], [ 13 , 14 , 15 , 16 ] ]) x2 = torch.from_numpy(x2).reshape( 1 , 1 , 4 , 4 ). float () avgpool4 = nn.AvgPool2d(kernel_size = 3 , stride = 2 , padding = 1 , ceil_mode = True ) y4 = avgpool4(x2) print (y4) # 打印结果 ''' tensor([[[[ 1.5556, 3.3333, 2.0000], [ 6.3333, 11.0000, 6.0000], [ 4.5000, 7.5000, 4.0000]]]]) ''' |
计算过程:
输出形状 = ceil[(4 - 3 + 2) / 2] + 1 = 3,
D[1,1] = (0+0+0+0+1+2+0+5+6) / 9 = 1.5556,
D[1,2] = (0+0+0+2+3+4+6+7+8) / 9 = 3.3333,
D[1,3] = (0+0+4+0+8+0) / 6 = 2,
D[2,1] = (0+5+6+0+9+10+0+13+14) / 9 = 6.3333,
D[2,2] = (6+7+8+10+11+12+14+15+16) / 9 = 11,
D[2,3] = (8+0+12+0+16+0) / 6 = 6,
D[3,1] = (0+13+14+0+0+0) / 6 = 4.5,
D[3,2] = (14+15+16+0+0+0) / 6 = 7.5,
D[3,3] = (16+0+0+0) / 4 = 4.
总结
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原文链接:https://blog.csdn.net/qq_38964360/article/details/129148451