C#定义多行字符串的方式
在定义的前面加上@符号：
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string aa = @"asdfsdfsd fsdsfsdfsdfsdfsdfsdfs safasfsadfsdfasfsfsdfsd "; |
在C#中拼接字符串有几种方法
1. 利用 JsonConvert.SerializeObject方法 (Nuget获取Newtonsoft.Json Package)，需要Newtonsoft.Json 支持。
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string uid = "22"; var abcObject = new{ AccessKey = 11, CustomerNo = uid, mc = "33", qd = "44", mr = "55", insertDate = DateTime.Now}; string serJson = JsonConvert.SerializeObject(abcObject); |
2. 利用StringBuilder
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StringBuilder str = new StringBuilder(); str.Append("{"); str.Append("AccessKey:\"" + 11 + "\","); str.Append("mc:\"" + 22 + "\","); str.Append("qd:\"" + 33 + "\""); str.Append("}"); string serJson = str.ToString(); |
3. 直接拼接字符串
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string json = "{\"speed\":" + speed + "," + "\"direction\":" + direction + "}"; TODO：输出{ "speed": 591, "direction": 0} |
"{\"Bool_Type\":\"Bool\",\"Int_Type\":6666666,\"Float_Type\": 66.99,\"String_Type\":\"这是String类型\",\"Vector2_Type\":{\"x\":666.0,\"y\":666.0},\"Vector3_Type\":{\"x\":666.0,\"y\":666.0,\"z\":666.0}}";
4. 利用StringFormat
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string mc = "22";string id = "11";string serJson = string.Format("[{{ AccessKey:\"{0}\",mc:\"{1}\"}},{{ AccessKey:\"{2}\",mc:\"{3}\"}}]", id, mc, "33", "44"); |
Jobject 数据结构的解析：
首先下载Newtonsoft.Json，增加引用using Newtonsoft.Json.Linq;
把jobject的内容提取出来，
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//Jobject的内容格式如下:{ "code": 200, "msg": "SUCCESS", "data": { "id": "12345678", "name": "张三", "sex": "男", "result": { "access_token": "49d58eacd7811e463429a1ae10b42173", "user_info": [{ "school": "社会大学", "major": "软件开发", "education": "本科", "score": 97 }, { "school": "湖南大学", "major": "软件工程", "education": "研究生", "score": 100 }] } }} |
可放到json官网在线JSON校验格式化工具里解析。
代码如下：
1，新建类：
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public class UserInfo{ public string id { get; set; } public string name { get; set; } public string sex { get; set; } public string access_token { get; set; } public string school { get; set; } public string major { get; set; } public string education { get; set; } public string score { get; set; }} |
2，获取值：
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JObject result = new JObject();//假设result为数据结构UserInfo userinfo = new UserInfo();userinfo.id = result["data"].Value<string>("id");//iduserinfo.name = result["data"].Value<string>("name"); //nameuserinfo.sex = result["data"].Value<string>("sex"); //sexuserinfo.access_token= result["data"]["result"]["access_token"].ToString();//access_tokenJArray res = result["data"]["result"].Value<JArray>("user_info");JObject obj = JObject.Parse(res[0].ToString());//只获取数据结构中第一个userinfo里的数据信息userinfo.school = obj.Value<string>("school"); //schoooluserinfo.major = obj.Value<string>("major");//majoruserinfo.education = obj.Value<string>("education");//educationuserinfo.score= obj.Value<string>("score");//score |
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原文链接：https://blog.csdn.net/qq_18427785/article/details/114519831
