JSONObject.toJSONString 过滤值为空的key
情况
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public static String getJsonResult( int status, String msg, Object data){undefined Map<String, Object> resultMap= new HashMap<String, Object>(); resultMap.put( "status" , status); resultMap.put( "msg" , msg); resultMap.put( "data" , data); return JSONObject.toJSONString(resultMap); } public static void main(String[] args) {undefined System.out.println(getJsonResult( 1 , "success" , null )); } |
结果
{"msg":"success","status":1}
从输出结果可以看出,null对应的key已经被过滤掉;这明显不是我们想要的结果,这时我们就需要用到fastjson的SerializerFeature序列化属性
也就是这个方法
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JSONObject.toJSONString(Object object, SerializerFeature... features) |
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public static String getJsonResult( int status, String msg, Object data){undefined Map<String, Object> resultMap= new HashMap<String, Object>(); resultMap.put( "status" , status); resultMap.put( "msg" , msg); resultMap.put( "data" , data); return JSONObject.toJSONString(resultMap,SerializerFeature.WriteMapNullValue); } |
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public static void main(String[] args) {undefined System.out.println(getJsonResult( 1 , "success" , null )); } |
结果
{"msg":"success","data":null,"status":1}
JSONObject.toJSONString自动过滤空值
使用fastjson将javabean转string时,默认会将值为null的属性过滤掉,
可通过设置SerializerFeature.WriteMapNullValue避免这种情况
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String value = JSONObject.toJSONString(objectData, SerializerFeature.WriteMapNullValue); |
以上为个人经验,希望能给大家一个参考,也希望大家多多支持服务器之家。
原文链接:https://blog.csdn.net/liu123342/article/details/82379738