代码
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# -*- coding: utf-8 -*- # Author : markadc from datetime import datetime, timedelta # 获取今天任意时刻的时间戳 def today_anytime_tsp(hour, minute, second = 0 ): now = datetime.now() today_0 = now - timedelta(hours = now.hour, minutes = now.minute, seconds = now.second) today_anytime = today_0 + timedelta(hours = hour, minutes = minute, seconds = second) tsp = today_anytime.timestamp() print ( '{} 的时间戳是 {}' . format (today_anytime, tsp)) return tsp if __name__ = = '__main__' : tsp = today_anytime_tsp( 18 , 15 , 23 ) # 获取今天18点15分23秒的时间戳 print (tsp) |
输出
ps:Python来获取昨天和今天的日期
这个问题也是常见问题,可能碰到这种问题我们就会这么写yesterday = today - 1,tomorrow = today + 1;这样写实际会报错,会提示不支持的操作类型。碰到时间差的问题的,优先考虑datetime模块中的timedelta。具体获取很简单
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>>> import datetime >>> today = datetime.date.today() # 今天 >>> yesterday = today - datetime.timedelta(days = 1 ) # 昨天 >>> tomorrow = today + datetime.timedelta(days = 1 ) # 明天 >>> print (yesterday,today,tomorrow) (datetime.date( 2018 , 7 , 31 ), datetime.date( 2018 , 8 , 1 ), datetime.date( 2018 , 8 , 2 )) >>> |
其他的也可以获取一秒后,一分钟,一小时,甚至一年的具体日期
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>>> import datetime >>> t1 = datetime.datetime.today() # 获取现在时间 >>> t1 datetime.datetime( 2018 , 8 , 1 , 21 , 34 , 19 , 924000 ) >>> t2 = t1 + datetime.timedelta(seconds = 1 ) # 获取一秒后的时间 >>> t2 datetime.datetime( 2018 , 8 , 1 , 21 , 34 , 20 , 924000 ) >>> t3 = t1 + datetime.timedelta(seconds = 60 ) # 获取一分后的时间 >>> t3 datetime.datetime( 2018 , 8 , 1 , 21 , 35 , 19 , 924000 ) >>> t4 = t1 + datetime.timedelta(seconds = 3600 ) # 获取一小时后的时间 >>> t4 datetime.datetime( 2018 , 8 , 1 , 22 , 34 , 19 , 924000 ) >>> today = datetime.date.today() # 获取当前日期 >>> anday = today + datetime.timedelta(days = 365 ) # 获取一年后日期 >>> print (anday) 2019 - 08 - 01 >>> |
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原文链接:https://blog.csdn.net/MarkAdc/article/details/125332525