服务器之家:专注于VPS、云服务器配置技术及软件下载分享
分类导航

PHP教程|ASP.NET教程|Java教程|ASP教程|编程技术|正则表达式|C/C++|IOS|C#|Swift|Android|VB|R语言|JavaScript|易语言|vb.net|

服务器之家 - 编程语言 - Android - Android从xml加载到View对象过程解析

Android从xml加载到View对象过程解析

2021-06-25 19:53周柯文 Android

这篇文章主要介绍了 Android从xml加载到View对象过程解析的相关资料,需要的朋友可以参考下

我们从Activity的setContentView()入手,开始源码解析,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
//Activity.setContentView
public void setContentView(int layoutResID) {
getWindow().setContentView(layoutResID);
initActionBar();
}
//PhoneWindow.setContentView
public void setContentView(int layoutResID) {
if (mContentParent == null) {
installDecor();
} else {
mContentParent.removeAllViews();
}
mLayoutInflater.inflate(layoutResID, mContentParent);
final Callback cb = getCallback();
if (cb != null && !isDestroyed()) {
cb.onContentChanged();
}
}

发现是使用mLayoutInflater创建View的,所以我们去LayoutInflater.inflate()里面看下,

?
1
2
3
4
5
6
7
8
9
public View inflate(int resource, ViewGroup root, boolean attachToRoot) {
if (DEBUG) System.out.println("INFLATING from resource: " + resource);
XmlResourceParser parser = getContext().getResources().getLayout(resource);
try {
return inflate(parser, root, attachToRoot);
} finally {
parser.close();
}
}

先根据resource id 获取到XmlResourceParseer,意如其名,就是xml的解析器,继续往下,进入到inflate的核心方法,有些长,我们只分析关键部分:

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
public View inflate(XmlPullParser parser, ViewGroup root, boolean attachToRoot) {
......
if (TAG_MERGE.equals(name)) {
if (root == null || !attachToRoot) {
throw new InflateException("<merge /> can be used only with a valid "
+ "ViewGroup root and attachToRoot=true");
}
rInflate(parser, root, attrs, false);
} else {
// Temp is the root view that was found in the xml
View temp;
if (TAG_1995.equals(name)) {
temp = new BlinkLayout(mContext, attrs);
} else {
temp = createViewFromTag(root, name, attrs);
}
......
} catch (XmlPullParserException e) {
InflateException ex = new InflateException(e.getMessage());
ex.initCause(e);
throw ex;
} catch (IOException e) {
InflateException ex = new InflateException(
parser.getPositionDescription()
+ ": " + e.getMessage());
ex.initCause(e);
throw ex;
} finally {
// Don't retain static reference on context.
mConstructorArgs[0] = lastContext;
mConstructorArgs[1] = null;
}
return result;
}
}

如果tag的名字不是TAG_1995(名字是个梗),就调用函数createViewFromTag()创建View,进去看看,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
View createViewFromTag(View parent, String name, AttributeSet attrs) {
if (name.equals("view")) {
name = attrs.getAttributeValue(null, "class");
}
......
View view;
if (mFactory2 != null) view = mFactory2.onCreateView(parent, name, mContext, attrs);
else if (mFactory != null) view = mFactory.onCreateView(name, mContext, attrs);
else view = null;
if (view == null && mPrivateFactory != null) {
view = mPrivateFactory.onCreateView(parent, name, mContext, attrs);
}
if (view == null) {
if (-1 == name.indexOf('.')) {
view = onCreateView(parent, name, attrs);
} else {
view = createView(name, null, attrs);
}
}
if (DEBUG) System.out.println("Created view is: " + view);
return view;
......
}

首先尝试用3个Fractory创建View,如果成功就直接返回了。注意,我们可以利用这个机制,创建自己的Factory来控制View的创建过程。

如果没有Factory或创建失败,那么走默认逻辑。

先判断name中是否有'.'字符,如果没有,则认为使用android自己的View,此时会在name的前面加上包名"android.view.";如果有这个'.',则认为使用的自定义View,这时无需添加任何前缀,认为name已经包含全包名了。

最终,使用这个全包名的name来创建实例,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
private static final HashMap<String, Constructor<? extends View>> sConstructorMap =
new HashMap<String, Constructor<? extends View>>();
protected View onCreateView(String name, AttributeSet attrs)
throws ClassNotFoundException {
return createView(name, "android.view.", attrs);
}
public final View createView(String name, String prefix, AttributeSet attrs)
throws ClassNotFoundException, InflateException {
Constructor<? extends View> constructor = sConstructorMap.get(name);
Class<? extends View> clazz = null;
   ......
if (constructor == null) {
// Class not found in the cache, see if it's real, and try to add it
clazz = mContext.getClassLoader().loadClass(
prefix != null ? (prefix + name) : name).asSubclass(View.class);
if (mFilter != null && clazz != null) {
boolean allowed = mFilter.onLoadClass(clazz);
if (!allowed) {
failNotAllowed(name, prefix, attrs);
}
}
constructor = clazz.getConstructor(mConstructorSignature);
sConstructorMap.put(name, constructor);
} else {
// If we have a filter, apply it to cached constructor
if (mFilter != null) {
// Have we seen this name before?
Boolean allowedState = mFilterMap.get(name);
if (allowedState == null) {
// New class -- remember whether it is allowed
clazz = mContext.getClassLoader().loadClass(
prefix != null ? (prefix + name) : name).asSubclass(View.class);
boolean allowed = clazz != null && mFilter.onLoadClass(clazz);
mFilterMap.put(name, allowed);
if (!allowed) {
failNotAllowed(name, prefix, attrs);
}
} else if (allowedState.equals(Boolean.FALSE)) {
failNotAllowed(name, prefix, attrs);
}
}
}
Object[] args = mConstructorArgs;
args[1] = attrs;
return constructor.newInstance(args);
......
}

从源码中看到,在创建实例前,会先从一个静态Map中获取缓存,

?
1
Constructor<? extends View> constructor = sConstructorMap.get(name);

缓存的是Constructor对象,目的是用于创建实例,这里要注意sConstructorMap是静态的,并且通过Constructor创建的实例,是使用和Constructor对象同一个ClassLoader来创建的,换句话说,在同一个进程中,同一个自定义View对象,是无法用不同ClassLoader加载的,如果想解决这个问题,就不要让系统使用createView()接口创建View,做法就是自定义Factory或Factory2来自行创建View。

继续往下看,如果缓存里没有,则创建View的Class对象clazz,并缓存到sConstructorMap中,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
if (constructor == null) {
// Class not found in the cache, see if it's real, and try to add it
clazz = mContext.getClassLoader().loadClass(
prefix != null ? (prefix + name) : name).asSubclass(View.class);
if (mFilter != null && clazz != null) {
boolean allowed = mFilter.onLoadClass(clazz);
if (!allowed) {
failNotAllowed(name, prefix, attrs);
}
}
constructor = clazz.getConstructor(mConstructorSignature);
sConstructorMap.put(name, constructor);
}

然后就是newInstance了,至此这个View便从xml中变成了java对象,我们继续返回到inflate函数中,看看这个View返回之后做了什么,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
......
// Temp is the root view that was found in the xml
View temp;
if (TAG_1995.equals(name)) {
temp = new BlinkLayout(mContext, attrs);
} else {
temp = createViewFromTag(root, name, attrs);
}
ViewGroup.LayoutParams params = null;
if (root != null) {
// Create layout params that match root, if supplied
params = root.generateLayoutParams(attrs);
if (!attachToRoot) {
// Set the layout params for temp if we are not
// attaching. (If we are, we use addView, below)
temp.setLayoutParams(params);
}
}
// Inflate all children under temp
rInflate(parser, temp, attrs, true);
// We are supposed to attach all the views we found (int temp)
// to root. Do that now.
if (root != null && attachToRoot) {
root.addView(temp, params);
}
// Decide whether to return the root that was passed in or the
// top view found in xml.
if (root == null || !attachToRoot) {
result = temp;
}
......
return result;

从createViewFromTag返回后,会调用个rInflate(),其中parent参数就是刚才创建出的View,应该能猜到里面做了什么,

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
void rInflate(XmlPullParser parser, View parent, final AttributeSet attrs,
boolean finishInflate) throws XmlPullParserException, IOException {
final int depth = parser.getDepth();
int type;
while (((type = parser.next()) != XmlPullParser.END_TAG ||
parser.getDepth() > depth) && type != XmlPullParser.END_DOCUMENT) {
if (type != XmlPullParser.START_TAG) {
continue;
}
final String name = parser.getName();
if (TAG_REQUEST_FOCUS.equals(name)) {
parseRequestFocus(parser, parent);
} else if (TAG_INCLUDE.equals(name)) {
if (parser.getDepth() == 0) {
throw new InflateException("<include /> cannot be the root element");
}
parseInclude(parser, parent, attrs);
} else if (TAG_MERGE.equals(name)) {
throw new InflateException("<merge /> must be the root element");
} else if (TAG_1995.equals(name)) {
final View view = new BlinkLayout(mContext, attrs);
final ViewGroup viewGroup = (ViewGroup) parent;
final ViewGroup.LayoutParams params = viewGroup.generateLayoutParams(attrs);
rInflate(parser, view, attrs, true);
viewGroup.addView(view, params);
} else {
final View view = createViewFromTag(parent, name, attrs);
final ViewGroup viewGroup = (ViewGroup) parent;
final ViewGroup.LayoutParams params = viewGroup.generateLayoutParams(attrs);
rInflate(parser, view, attrs, true);
viewGroup.addView(view, params);
}
}
if (finishInflate) parent.onFinishInflate();
}

没错,就是递归的使用createViewFromTag()创建子View,并通过ViewGroup.addView添加到parent view中。

之后,这个View树上的所有View都创建完毕。然后会根据inflate()的参数(root和attachToRoot)判断是否将新创建的View添加到root view中,

?
1
2
3
if (root != null && attachToRoot) {
root.addView(temp, params);
}

然后,inflate()就将View返回了。

以上内容是小编给大家介绍的android从xml加载到view对象过程解析,希望对大家有所帮助!

延伸 · 阅读

精彩推荐
  • AndroidAndroid实现Service获取当前位置(GPS+基站)的方法

    Android实现Service获取当前位置(GPS+基站)的方法

    这篇文章主要介绍了Android实现Service获取当前位置(GPS+基站)的方法,较为详细的分析了Service基于GPS位置的技巧,具有一定参考借鉴价值,需要的朋友可以参考下...

    Ruthless8342021-03-31
  • AndroidAndroid实现固定屏幕显示的方法

    Android实现固定屏幕显示的方法

    这篇文章主要介绍了Android实现固定屏幕显示的方法,实例分析了Android屏幕固定显示所涉及的相关技巧,具有一定参考借鉴价值,需要的朋友可以参考下...

    鉴客6192021-03-27
  • AndroidAndroid程序设计之AIDL实例详解

    Android程序设计之AIDL实例详解

    这篇文章主要介绍了Android程序设计的AIDL,以一个完整实例的形式较为详细的讲述了AIDL的原理及实现方法,需要的朋友可以参考下...

    Android开发网4642021-03-09
  • AndroidAndroid中AsyncTask详细介绍

    Android中AsyncTask详细介绍

    这篇文章主要介绍了Android中AsyncTask详细介绍,AsyncTask是一个很常用的API,尤其异步处理数据并将数据应用到视图的操作场合,需要的朋友可以参考下...

    Android开发网7452021-03-11
  • Android汇总Android视频录制中常见问题

    汇总Android视频录制中常见问题

    这篇文章主要汇总了Android视频录制中常见问题,帮助大家更好地解决Android视频录制中常见的问题,需要的朋友可以参考下...

    yh_thu5192021-04-28
  • AndroidAndroid CardView+ViewPager实现ViewPager翻页动画的方法

    Android CardView+ViewPager实现ViewPager翻页动画的方法

    本篇文章主要介绍了Android CardView+ViewPager实现ViewPager翻页动画的方法,小编觉得挺不错的,现在分享给大家,也给大家做个参考。一起跟随小编过来看看吧...

    Abby代黎明9602022-03-02
  • AndroidAndroid编程解析XML方法详解(SAX,DOM与PULL)

    Android编程解析XML方法详解(SAX,DOM与PULL)

    这篇文章主要介绍了Android编程解析XML方法,结合实例形式详细分析了Android解析XML文件的常用方法与相关实现技巧,需要的朋友可以参考下...

    liuhe68810052021-05-03
  • AndroidAndroid界面效果UI开发资料汇总(附资料包)

    Android界面效果UI开发资料汇总(附资料包)

    android ui界面设计,友好的界面会提高用户体验度;同时也增强了android ui界面设计的难度,本文提供了一些常用开发资料(有下载哦)感兴趣的朋友可以了解下...

    Android开发网4672021-01-03